Arithmatic Progression - Exercise 5.3
Karnataka State Board - Exercise 1.3
Practice the exercises and find video solutions for Arithmatic Progression
In a potato race, a bucket is placed at the starting point, which is 5 m
In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are 10 potatoes in the line. A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and he continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to
In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are 10 potatoes in the line. A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and he continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to
In a potato race, a bucket is placed at the starting point, which is 5 m
In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are 10 potatoes in the line. A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and he continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Fig. 5.5). In how many rows are the 200 logs placed and how many logs are in the top row? mathematicsexercise 5.3 question number 19 mathematicsexercise 1.3 question number 19 study safely at home
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Fig. 5.5). In how many rows are the 200 logs placed and how many logs are in the top row? mathematicsexercise 5.3 question number 19 mathematicsexercise 1.3 question number 19 study safely at home
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row
200 logs are stacked in the following manner: 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Fig. 5.5). In how many rows are the 200 logs placed and how many logs are in the top row? mathematicsexercise 5.3 question number 19 mathematicsexercise 1.3 question number 19 study safely at home
A spiral is made up of successive semicircles, with centres alternately at A
A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, . . .as shown in Fig. 5.4. What is the total length of such a spiral made up of thirteen consecutive semicircles? [Take π = 22/7] mathematicsexercise 5.3 question number 18 SSLC mathematicsexercise 1.3 question number 18
A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, . . .as shown in Fig. 5.4. What is the total length of such a spiral made up of thirteen consecutive semicircles? [Take π = 22/7] mathematicsexercise 5.3 question number 18 SSLC mathematicsexercise 1.3 question number 18
A spiral is made up of successive semicircles, with centres alternately at A
A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm, . . .as shown in Fig. 5.4. What is the total length of such a spiral made up of thirteen consecutive semicircles? [Take π = 22/7] mathematicsexercise 5.3 question number 18 SSLC mathematicsexercise 1.3 question number 18
In a school, students thought of planting trees in and around the school to reduce
In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students? mathematics exercise
In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students? mathematics exercise
In a school, students thought of planting trees in and around the school to reduce
In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, e.g., a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students? mathematics exercise
A sum of ₹ 700 is to be used to give seven cash prizes to students of a school
A sum of ₹ 700 is to be used to give seven cash prizes to students of a school
A contract on construction job specifies a penalty for delay of completion beyond a
A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200 for the first day, ₹ 250 for the second day, ₹ 300 for the third day, etc., the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty if he has delayed the work by 30 days? mathematicsexercise 5.3 question number 15 SSLC mathematicsexercise 1.3 question number 15 arithmetic progressionformula: sn
A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200 for the first day, ₹ 250 for the second day, ₹ 300 for the third day, etc., the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty if he has delayed the work by 30 days? mathematicsexercise 5.3 question number 15 SSLC mathematicsexercise 1.3 question number 15 arithmetic progressionformula: sn
A contract on construction job specifies a penalty for delay of completion beyond a
A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: ₹ 200 for the first day, ₹ 250 for the second day, ₹ 300 for the third day, etc., the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty if he has delayed the work by 30 days? mathematicsexercise 5.3 question number 15 SSLC mathematicsexercise 1.3 question number 15 arithmetic progressionformula: sn
The sum of the odd numbers between 0 and 50 is 625 mathematics
The sum of the odd numbers between 0 and 50 is 625 mathematics exercise 5.3question number 14SSLC mathematicsexercise 1.3 question number 14
The sum of the odd numbers between 0 and 50 is 625 mathematics exercise 5.3question number 14SSLC mathematicsexercise 1.3 question number 14
The sum of the odd numbers between 0 and 50 is 625 mathematics
The sum of the odd numbers between 0 and 50 is 625 mathematics exercise 5.3question number 14SSLC mathematicsexercise 1.3 question number 14
13. Find the sum of the first 15 multiples of 8.
13. Find the sum of the first 15 multiples of 8. mathematicsexercise 5.3question number 13 mathematicsexercise 1.3question number 13
13. Find the sum of the first 15 multiples of 8. mathematicsexercise 5.3question number 13 mathematicsexercise 1.3question number 13
13. Find the sum of the first 15 multiples of 8.
13. Find the sum of the first 15 multiples of 8. mathematicsexercise 5.3question number 13 mathematicsexercise 1.3question number 13
Find the sum of first 40 positive integers divisible by 6. 10
Find the sum of first 40 positive integers divisible by 6. 10
If the sum of the first n terms of an AP is 4n - n2, what is the first term
If the sum of the first n terms of an AP is 4n - n2, what is the first term (that is S1)? What is the sum of the first two terms? What is the second term? Similarly, find the 3rd, the 10th and the nth terms. class 10 Mathematicsexercise 5.3question number 11 SSLC mathematicsexercise 1.3question number 11
If the sum of the first n terms of an AP is 4n - n2, what is the first term (that is S1)? What is the sum of the first two terms? What is the second term? Similarly, find the 3rd, the 10th and the nth terms. class 10 Mathematicsexercise 5.3question number 11 SSLC mathematicsexercise 1.3question number 11
If the sum of the first n terms of an AP is 4n - n2, what is the first term
If the sum of the first n terms of an AP is 4n - n2, what is the first term (that is S1)? What is the sum of the first two terms? What is the second term? Similarly, find the 3rd, the 10th and the nth terms. class 10 Mathematicsexercise 5.3question number 11 SSLC mathematicsexercise 1.3question number 11
Show that a₁, a₂,... , aₙ, ... form an AP where aₙ (ii) aₙ = 9 - 5n. s15=?
Show that a₁, a₂,... , aₙ, ... form an AP where aₙ is defined as below :(i) aₙ = 3 + 4n (ii) aₙ = 9 - 5nAlso, find the sum of the first 15 terms in each casecbse class 10 Mathematics exercise 5.3question number 10(I)SSLC mathematicsexercise 1.3question number 10(1)
Show that a₁, a₂,... , aₙ, ... form an AP where aₙ is defined as below :(i) aₙ = 3 + 4n (ii) aₙ = 9 - 5nAlso, find the sum of the first 15 terms in each casecbse class 10 Mathematics exercise 5.3question number 10(I)SSLC mathematicsexercise 1.3question number 10(1)
Show that a₁, a₂,... , aₙ, ... form an AP where aₙ (ii) aₙ = 9 - 5n. s15=?
Show that a₁, a₂,... , aₙ, ... form an AP where aₙ is defined as below :(i) aₙ = 3 + 4n (ii) aₙ = 9 - 5nAlso, find the sum of the first 15 terms in each casecbse class 10 Mathematics exercise 5.3question number 10(I)SSLC mathematicsexercise 1.3question number 10(1)
9. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum
9. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms. CBSE class 10 Mathematicsexercise 5.3question number 9 SSLC mathematicsexercise 1.3question number 9
9. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms. CBSE class 10 Mathematicsexercise 5.3question number 9 SSLC mathematicsexercise 1.3question number 9
9. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum
9. If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms. CBSE class 10 Mathematicsexercise 5.3question number 9 SSLC mathematicsexercise 1.3question number 9
8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18
8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18respectively. mathematicsexercise 5.3q n.8 mathematicsexercise 1.3q.n. 8
8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18respectively. mathematicsexercise 5.3q n.8 mathematicsexercise 1.3q.n. 8
8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18
8. Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18respectively. mathematicsexercise 5.3q n.8 mathematicsexercise 1.3q.n. 8
7. Find the sum of the first 22 terms of an AP in which d = 7 and 22nd term is 149
7. Find the sum of the first 22 terms of an AP in which d = 7 and 22nd term is 149 CBSE class 10 Mathematicsexercise 5.3SSLC mathematicsexercise 1.3
7. Find the sum of the first 22 terms of an AP in which d = 7 and 22nd term is 149 CBSE class 10 Mathematicsexercise 5.3SSLC mathematicsexercise 1.3
7. Find the sum of the first 22 terms of an AP in which d = 7 and 22nd term is 149
7. Find the sum of the first 22 terms of an AP in which d = 7 and 22nd term is 149 CBSE class 10 Mathematicsexercise 5.3SSLC mathematicsexercise 1.3
6. The first and the last term of an AP are 17 and 350 respectively.
6. The first and the last term of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum? mathematics exercise 5.3SSLC mathematics exercise 1.3
6. The first and the last term of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum? mathematics exercise 5.3SSLC mathematics exercise 1.3
6. The first and the last term of an AP are 17 and 350 respectively.
6. The first and the last term of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum? mathematics exercise 5.3SSLC mathematics exercise 1.3
The first term of an AP is 5, the last term is 45 and the sum is 400. Find the n and d
The first term of an AP is 5, the last term is 45 and the sum is 400. Find the n and d
How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of 636?
How many terms of the AP : 9, 17, 25, . . . must be taken to give a sum of 636?
(x) Given l = 28, S = 144 and there are total 9 terms. Find a
3) (x) Given l = 28, S = 144 and there are total 9 terms. Find a mathematics exercise 5.3 number 3 (10) mathematics 1.3question number 3(10)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3) (x) Given l = 28, S = 144 and there are total 9 terms. Find a mathematics exercise 5.3 number 3 (10) mathematics 1.3question number 3(10)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
(x) Given l = 28, S = 144 and there are total 9 terms. Find a
3) (x) Given l = 28, S = 144 and there are total 9 terms. Find a mathematics exercise 5.3 number 3 (10) mathematics 1.3question number 3(10)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
(ix) Given a = 3, n = 8, S = 192 , find d. maths
3)(ix) Given a = 3, n = 8, S = 192 , find d. mathematics exercise 5.3 number 3 (9) mathematics 1.3question number 3(9)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(ix) Given a = 3, n = 8, S = 192 , find d. mathematics exercise 5.3 number 3 (9) mathematics 1.3question number 3(9)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
(ix) Given a = 3, n = 8, S = 192 , find d. maths
3)(ix) Given a = 3, n = 8, S = 192 , find d. mathematics exercise 5.3 number 3 (9) mathematics 1.3question number 3(9)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
(viii) Given aₙ = 4, d = 2, Sₙ = - 14 , find n and a
3) (viii) Given aₙ = 4, d = 2, Sₙ = - 14 , find n and a mathematics exercise 5.3 number 3 (8) mathematics 1.3question number 3(8)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3) (viii) Given aₙ = 4, d = 2, Sₙ = - 14 , find n and a mathematics exercise 5.3 number 3 (8) mathematics 1.3question number 3(8)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
(viii) Given aₙ = 4, d = 2, Sₙ = - 14 , find n and a
3) (viii) Given aₙ = 4, d = 2, Sₙ = - 14 , find n and a mathematics exercise 5.3 number 3 (8) mathematics 1.3question number 3(8)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(7)a=8,an=62,Sn=210, find n and d
3)7)a=8,an=62,Sn=210, find n and d mathematics exercise 5.3 number 3 (7) mathematics 1.3question number 3(7)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)7)a=8,an=62,Sn=210, find n and d mathematics exercise 5.3 number 3 (7) mathematics 1.3question number 3(7)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(7)a=8,an=62,Sn=210, find n and d
3)7)a=8,an=62,Sn=210, find n and d mathematics exercise 5.3 number 3 (7) mathematics 1.3question number 3(7)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(6)given a=2,d=8,Sn=90, find nand an maths
mathematics exercise 5.3 number 3 (6) mathematics 1.3question number 3(6)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
mathematics exercise 5.3 number 3 (6) mathematics 1.3question number 3(6)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(6)given a=2,d=8,Sn=90, find nand an maths
mathematics exercise 5.3 number 3 (6) mathematics 1.3question number 3(6)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(5)d=5,S,9=75, find a and a9
3) In an Ap 5) d=15, S9=75,a=?,a9=? mathematics exercise 5.3 number 3 (5) mathematics 1.3question number 3(5)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3) In an Ap 5) d=15, S9=75,a=?,a9=? mathematics exercise 5.3 number 3 (5) mathematics 1.3question number 3(5)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
3)(5)d=5,S,9=75, find a and a9
3) In an Ap 5) d=15, S9=75,a=?,a9=? mathematics exercise 5.3 number 3 (5) mathematics 1.3question number 3(5)formula: an = a+(n-1)dSn= n/2(2a+(n-2)d)
A3=15,S10=125, find d and a10
3) In an Ap 4) a3=15, S10=125,d=?,a10=? mathematics exercise 5.3 number 3 (4) mathematics 1.3question number 3(4)formula: an = a+(n-1)dSn= n/2(a+l)
3) In an Ap 4) a3=15, S10=125,d=?,a10=? mathematics exercise 5.3 number 3 (4) mathematics 1.3question number 3(4)formula: an = a+(n-1)dSn= n/2(a+l)
A3=15,S10=125, find d and a10
3) In an Ap 4) a3=15, S10=125,d=?,a10=? mathematics exercise 5.3 number 3 (4) mathematics 1.3question number 3(4)formula: an = a+(n-1)dSn= n/2(a+l)
a12=37,d=3, find a ,S12
3) In an Ap 3) a12=37, d= 3,a=?,S12=? mathematics exercise 5.3 number 3 (3) mathematics 1.3question number 3(3)formula: an = a+(n-1)dSn= n/2(a+l)
3) In an Ap 3) a12=37, d= 3,a=?,S12=? mathematics exercise 5.3 number 3 (3) mathematics 1.3question number 3(3)formula: an = a+(n-1)dSn= n/2(a+l)
a12=37,d=3, find a ,S12
3) In an Ap 3) a12=37, d= 3,a=?,S12=? mathematics exercise 5.3 number 3 (3) mathematics 1.3question number 3(3)formula: an = a+(n-1)dSn= n/2(a+l)
a=7,a13=35, d=?S13=?
3) In an Ap 2) a=7,a13= 35, d=?,S13=? mathematics exercise 5.3 number 3 (2) mathematics 1.3question number 3(2)formula: an = a+(n-1)dSn= n/2(a+l)
3) In an Ap 2) a=7,a13= 35, d=?,S13=? mathematics exercise 5.3 number 3 (2) mathematics 1.3question number 3(2)formula: an = a+(n-1)dSn= n/2(a+l)
a=7,a13=35, d=?S13=?
3) In an Ap 2) a=7,a13= 35, d=?,S13=? mathematics exercise 5.3 number 3 (2) mathematics 1.3question number 3(2)formula: an = a+(n-1)dSn= n/2(a+l)
In an Ap 1) a=5,d=3,an= 50, n=?,Sn=? maths maths
3) In an Ap 1) a=5,d=3,an= 50, n=?,Sn=? mathematics exercise 5.3 number 3 (1) mathematics 1.3question number 3(1)formula: an = a+(n-1)dSn= n/2(a+l)
3) In an Ap 1) a=5,d=3,an= 50, n=?,Sn=? mathematics exercise 5.3 number 3 (1) mathematics 1.3question number 3(1)formula: an = a+(n-1)dSn= n/2(a+l)
In an Ap 1) a=5,d=3,an= 50, n=?,Sn=? maths maths
3) In an Ap 1) a=5,d=3,an= 50, n=?,Sn=? mathematics exercise 5.3 number 3 (1) mathematics 1.3question number 3(1)formula: an = a+(n-1)dSn= n/2(a+l)
Find the sum of the AP -5+ -8+ -11,.. mathematics
2. Find the sum of the AP (3) -5 +- 3+-11+,.….…+ - 230Find the number of terms by using the formula an = a +(n-1)dfind the sum by using the formula Sn = n/2(a+l)
2. Find the sum of the AP (3) -5 +- 3+-11+,.….…+ - 230Find the number of terms by using the formula an = a +(n-1)dfind the sum by using the formula Sn = n/2(a+l)
Find the sum of the AP -5+ -8+ -11,.. mathematics
2. Find the sum of the AP (3) -5 +- 3+-11+,.….…+ - 230Find the number of terms by using the formula an = a +(n-1)dfind the sum by using the formula Sn = n/2(a+l)
Find the sum of the AP mathematics
2. Find the sum of the AP (2) 34+32+30+..…...+10Find the number of terms by using the formula an = a +(n-1)dfind the sum by using the formula Sn = n/2(a+l)
2. Find the sum of the AP (2) 34+32+30+..…...+10Find the number of terms by using the formula an = a +(n-1)dfind the sum by using the formula Sn = n/2(a+l)
Find the sum of the AP mathematics
2. Find the sum of the AP (2) 34+32+30+..…...+10Find the number of terms by using the formula an = a +(n-1)dfind the sum by using the formula Sn = n/2(a+l)
Find the sum
10 cbse progression exercise 5.3 question number 2(1) SSLC mathematics exercise 1.3question number 2(1)Find the sum of the AP 7+10 1/2, ..… here a,d,and the last terms are given. So, we have to find number of termsFormula: an = a+ (n-1)dSn = n/2(a+l)
10 cbse progression exercise 5.3 question number 2(1) SSLC mathematics exercise 1.3question number 2(1)Find the sum of the AP 7+10 1/2, ..… here a,d,and the last terms are given. So, we have to find number of termsFormula: an = a+ (n-1)dSn = n/2(a+l)
Find the sum
10 cbse progression exercise 5.3 question number 2(1) SSLC mathematics exercise 1.3question number 2(1)Find the sum of the AP 7+10 1/2, ..… here a,d,and the last terms are given. So, we have to find number of termsFormula: an = a+ (n-1)dSn = n/2(a+l)
Find the sum of the AP 1/15,1/12,... to 11 terms
10 cbse progression exercise 5.3 question number 1(4) SSLC mathematics exercise 1.3question number 1(4)Find the sum of the AP 1/15,1/12, ..... to 11 terms. Formula: an = a+ (n-1)dSn = n/2
10 cbse progression exercise 5.3 question number 1(4) SSLC mathematics exercise 1.3question number 1(4)Find the sum of the AP 1/15,1/12, ..... to 11 terms. Formula: an = a+ (n-1)dSn = n/2
Find the sum of the AP 1/15,1/12,... to 11 terms
10 cbse progression exercise 5.3 question number 1(4) SSLC mathematics exercise 1.3question number 1(4)Find the sum of the AP 1/15,1/12, ..... to 11 terms. Formula: an = a+ (n-1)dSn = n/2
Find the sum of the AP 0.6,1.7,2.8..to 100 terms
Find the sum of the AP 0.6,1.7,2.8,,,,,to 100terms class 10 Mathematics exercise 5.3question number 1 mathematics exercise 1.3 question number 1The problem is solved through animated video
Find the sum of the AP 0.6,1.7,2.8,,,,,to 100terms class 10 Mathematics exercise 5.3question number 1 mathematics exercise 1.3 question number 1The problem is solved through animated video
Find the sum of the AP 0.6,1.7,2.8..to 100 terms
Find the sum of the AP 0.6,1.7,2.8,,,,,to 100terms class 10 Mathematics exercise 5.3question number 1 mathematics exercise 1.3 question number 1The problem is solved through animated video
find the sum of the AP -37,-33,--12 upto 12 terms| exercise 3
Arithmetic progressionexercise 3CBSE class 10 MathematicsSSLC mathematicsformula sn= n/2(2a+(n-1)d
Arithmetic progressionexercise 3CBSE class 10 MathematicsSSLC mathematicsformula sn= n/2(2a+(n-1)d
find the sum of the AP -37,-33,--12 upto 12 terms| exercise 3
Arithmetic progressionexercise 3CBSE class 10 MathematicsSSLC mathematicsformula sn= n/2(2a+(n-1)d
Find the sum
1)Find the sum the AP 2,7,12,..... upto 10 terms.The question is taken from CBSE class 10 Mathematicsexercise 5.3 question number 1(1)SSLC mathematics exercise 1.3 question number 1(1)solved through animated video
1)Find the sum the AP 2,7,12,..... upto 10 terms.The question is taken from CBSE class 10 Mathematicsexercise 5.3 question number 1(1)SSLC mathematics exercise 1.3 question number 1(1)solved through animated video
Find the sum
1)Find the sum the AP 2,7,12,..... upto 10 terms.The question is taken from CBSE class 10 Mathematicsexercise 5.3 question number 1(1)SSLC mathematics exercise 1.3 question number 1(1)solved through animated video
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